A common-emitter stage uses VCC = 12 V, R1 = 47 kΩ, R2 = 10 kΩ, RC = 2.2 kΩ, RE = 1 kΩ, with β = 150.
Base voltage, from the divider:
VB = 12 × 10 ÷ (47 + 10) = 12 × 0.1754 = 2.105 V
Emitter voltage, allowing 0.7 V across the base-emitter junction:
VE = 2.105 − 0.7 = 1.405 V
Emitter current:
IE = 1.405 ÷ 1,000 = 1.405 mA
Taking IC ≈ IE, the collector voltage is:
VC = 12 − (1.405 mA × 2.2 kΩ) = 12 − 3.092 = 8.908 V
So VCE = 8.908 − 1.405 = 7.503 V
That sits comfortably in the active region, roughly mid-rail, which is what you want for maximum undistorted swing.
Why this bias arrangement. The emitter resistor provides negative feedback: if IC rises, VE rises, which reduces the base-emitter voltage and pushes IC back down. That makes the operating point far less sensitive to β, which varies widely between devices and with temperature. A design whose Q-point depends on β is not manufacturable, and saying so is often worth more than the arithmetic.