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Linear Integrated Circuits 555 Timer, 741, LM317, PLL & Online Tutoring

Linear integrated circuits (linear ICs) are analog chips that process continuously varying signals: op-amps, timers, voltage regulators, comparators, phase-locked loops and data converters. This page works the calculations linear IC courses test, from 555 timer frequency and LM317 resistor choice to Schmitt trigger thresholds, PLL lock range and DAC resolution, each with real component values. FLN Tutors (Freelancer Network) also offers one-to-one help. Matched to a verified specialist who knows your course, your university's marking criteria, and your deadline.

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FLN offers one-to-one online Linear integrated Circuits tutoring with verified subject specialists. Sessions focus on calculations, design problems and the theory behind them, including Operational Amplifiers, Comparators, Active Filters and Oscillators, using your own course material, so you understand the subject and can apply it yourself.

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What linear integrated circuits are

An integrated circuit puts transistors, resistors and sometimes capacitors on one piece of silicon. A linear (analog) IC works with signals that vary continuously, where a digital IC works with two levels, 0 and 1.

FamilyCommon ICsWhat they do
Operational amplifiers741, LM358, TL081Amplify, add, integrate, filter
Timers555, 556Generate pulses and square waves
Voltage regulators7805, 7812, LM317Hold a supply voltage steady
ComparatorsLM311, LM339Compare two voltages and switch
Phase-locked loops565, CD4046Lock onto and track a frequency
Data convertersDAC0808, ADC0804Convert between analog and digital

Classification examiners ask for: by function, linear versus digital; by scale of integration, SSI, MSI, LSI and VLSI; and by package, the 8-pin DIP used by the 741 and 555 being the one to draw.

For ideal op-amp configurations, real op-amp limitations and filter cutoff calculations, see the analog electronics page; this page concentrates on the specific ICs and their design calculations.

IC 741: pins and key specifications

The 741 is the op-amp most syllabuses use to teach specifications, even though modern designs usually choose a better part.

PinFunction
1 and 5Offset null
2Inverting input (−)
3Non-inverting input (+)
4Negative supply, −V
6Output
7Positive supply, +V
8No connection
ParameterTypical value for the 741Ideal op-amp
Open-loop voltage gain200,000 (106 dB)Infinite
Input resistance2 MΩInfinite
Output resistance75 ΩZero
Input offset voltage1 mVZero
Input bias current80 nAZero
CMRR90 dBInfinite
Slew rate0.5 V/µsInfinite
Gain-bandwidth productabout 1 MHzInfinite

How to use the table in an answer: state the typical value, then the ideal value, then what the difference does in practice. The low slew rate, for example, is why a 741 cannot reproduce a large, fast square wave.

Worked example: 555 timer astable and monostable

In astable mode the 555 runs continuously, producing a square wave. The capacitor charges through RA and RB and discharges through RB only:

  • t_high = 0.693 (RA + RB) C
  • t_low = 0.693 RB C
  • f = 1 ÷ (t_high + t_low), often written f ≈ 1.44 ÷ ((RA + 2RB) C)

With RA = 4.7 kΩ, RB = 10 kΩ and C = 10 nF:

QuantityWorkingResult
t_high0.693 × 14.7 kΩ × 10 nF101.87 µs
t_low0.693 × 10 kΩ × 10 nF69.3 µs
Period T101.87 + 69.3171.17 µs
Frequency1 ÷ 171.17 µs5,842 Hz
Duty cycle101.87 ÷ 171.1759.5%

The 1.44 shortcut gives 5,830 Hz. The small difference comes from rounding 1 ÷ 0.693 to 1.44, so say which formula you used.

Why the duty cycle is always above 50%: the capacitor charges through both resistors but discharges through RB alone, so t_high is always longer. A diode across RB lets it charge through RA only, which allows a duty cycle of 50% or less.

Monostable mode gives one pulse per trigger, of width T = 1.1 RC. With R = 100 kΩ and C = 10 µF, T = 1.1 × 100,000 × 0.00001 = 1.1 seconds.

Voltage regulators: 7805 and LM317

Fixed regulators. The 78xx series gives a fixed positive output: 7805 gives 5 V and 7812 gives 12 V, while the 79xx series gives negative outputs. Each needs its input about 2 V above the output, called the dropout voltage, so a 7805 needs at least about 7 V in.

The heat they produce is the calculation students forget. A regulator burns off the difference between input and output:

P = (V_in − V_out) × I

A 7805 fed from 12 V and supplying 0.5 A dissipates (12 − 5) × 0.5 = 3.5 W, which needs a heatsink.

Adjustable regulator: worked LM317 design. The LM317 holds 1.25 V between its output and adjust pins, so:

V_out = 1.25 × (1 + R2 ÷ R1), ignoring the small adjust-pin current

  1. Take the usual R1 = 240 Ω.
  2. For 5 V: R2 = R1 × (V_out ÷ 1.25 − 1) = 240 × (4 − 1) = 720 Ω.
  3. 720 Ω is not a standard value. The nearest standard value, 750 Ω, gives 1.25 × (1 + 750 ÷ 240) = 5.156 V.
  4. The adjust-pin current, typically 50 µA, adds about 50 µA × 750 Ω = 37.5 mV, which is why precise designs measure and trim.
  5. Fed from 15 V at 0.5 A, it dissipates (15 − 5) × 0.5 = 5 W.

For 12 V, R2 = 2.2 kΩ gives 1.25 × (1 + 2,200 ÷ 240) = 12.708 V.

Worked example: a Schmitt trigger

A comparator switches when its input crosses a reference. With a noisy input, it can switch many times around that point. A Schmitt trigger adds positive feedback, giving two thresholds so that the output switches cleanly once.

Inverting Schmitt trigger: the input goes to the inverting pin, and R1 (feedback) and R2 (to ground) feed a fraction of the output back to the non-inverting pin. The feedback fraction is β = R2 ÷ (R1 + R2).

With output saturation at ±13 V, R1 = 10 kΩ and R2 = 2.2 kΩ:

  1. β = 2.2 ÷ 12.2 = 0.1803
  2. Upper threshold: +13 × 0.1803 = +2.34 V
  3. Lower threshold: −13 × 0.1803 = −2.34 V
  4. Hysteresis: 2.34 − (−2.34) = 4.69 V

The output only changes state when the input rises above +2.34 V or falls below −2.34 V, so noise smaller than 4.69 V peak to peak cannot cause false switching.

The trade-off to mention: more hysteresis rejects more noise, but the input must swing further before the output responds. Choose R2 to suit the noise you expect.

Worked example: instrumentation amplifier gain

An instrumentation amplifier amplifies the small difference between two inputs while rejecting voltages common to both. That makes it the standard choice for strain gauges, thermocouples and ECG electrodes.

The three-op-amp design. Two input buffers share a gain resistor R_G, followed by a difference amplifier. With equal resistors R in the first stage and a unity-gain difference stage:

G = 1 + 2R ÷ R_G

With R = 10 kΩ and R_G = 1 kΩ: G = 1 + 20,000 ÷ 1,000 = 21.

Changing one resistor, R_G, sets the gain without upsetting the balance of the circuit. That single-resistor adjustment is the reason the design exists.

Single-chip versions give the gain formula on the datasheet. A common part uses G = 1 + 49.4 kΩ ÷ R_G, so a gain of 100 needs R_G = 49.4 kΩ ÷ 99 = 499 Ω, which is a standard 1% value.

Why not use one op-amp? A single difference amplifier has low input resistance and needs four matched resistors to keep a high CMRR. The instrumentation amplifier has very high input resistance on both inputs and keeps its CMRR when the gain is changed.

Worked example: the 565 phase-locked loop

A phase-locked loop compares the phase of an input signal with a voltage-controlled oscillator (VCO) and adjusts the VCO until the two match. Its three blocks are the phase detector, a low-pass filter and the VCO. PLLs are used for FM demodulation, frequency synthesis and clock recovery.

Two ranges to define:

  • Lock range: the band of frequencies over which the PLL stays locked once it has locked.
  • Capture range: the narrower band over which it can acquire lock from an unlocked state.

Worked with the standard textbook relations for the 565, with R1 = 10 kΩ, C1 = 0.01 µF, supplies of ±10 V (so V = 20 V) and filter capacitor C2 = 10 µF:

QuantityFormulaResult
Free-running frequencyf0 = 0.3 ÷ (R1 C1)3,000 Hz
Lock rangef_L = ±8 f0 ÷ V±1,200 Hz
Capture rangef_C = ±(1 ÷ 2π) √(2π f_L ÷ (3.6 × 10³ × C2))±72.84 Hz

The capture range is always narrower than the lock range, which is the comparison examiners ask for. Increasing C2 narrows the capture range further, rejecting more noise but making lock slower to acquire.

Data converters: DAC and ADC resolution

A digital-to-analog converter (DAC) turns a binary number into a voltage. The R-2R ladder is the usual design taught, because it needs only two resistor values however many bits there are.

Resolution of an 8-bit DAC with a 5 V reference:

  • Number of steps: 2⁸ = 256
  • Step size: 5 V ÷ 256 = 19.53 mV
  • Largest output, at code 11111111: 5 × 255 ÷ 256 = 4.98 V, one step below the reference

An analog-to-digital converter (ADC) does the reverse. The successive-approximation type tests one bit per clock cycle, so an 8-bit conversion with a 1 MHz clock takes about 8 × 1 µs = 8 µs, plus a few cycles of overhead. Flash ADCs are much faster but need 2ⁿ − 1 comparators, which is why they are limited to low resolutions.

The step size is the smallest voltage change the system can represent. Quantisation error is up to half of one step either way.

Where students lose marks

  • Mixing up the 555 formulas: t_high uses RA + RB, t_low uses RB only.
  • Claiming a basic 555 astable can give a duty cycle below 50% without a diode.
  • Using the monostable constant 1.1 in an astable calculation, or 0.693 in a monostable one.
  • Writing an LM317 answer with a non-standard resistor value and no comment.
  • Leaving out regulator power dissipation and the heatsink it implies.
  • Forgetting the dropout voltage when choosing a regulator's input supply.
  • Drawing a Schmitt trigger with negative feedback, which makes it an amplifier.
  • Confusing lock range with capture range, or saying the capture range is wider.
  • Saying an n-bit DAC reaches its full reference voltage; it stops one step short.
  • Repeating ideal op-amp values when the question asks for 741 typical values.

See analog electronics help for op-amp configurations, real op-amp limits and filters, digital electronics help for logic and counters, power electronics help for switching converters, microcontrollers help for timers and ADCs on a chip, and electrical measurements help for measuring the circuits you build.

If a 555, regulator or PLL calculation will not come out right, send it over with your working and a tutor will show you where it goes wrong.

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Linear integrated Circuits tutoring: frequently asked questions

What is a linear integrated circuit?

A linear integrated circuit is an analog chip that processes signals varying continuously, rather than switching between two digital levels. Common examples are operational amplifiers such as the 741, the 555 timer, voltage regulators such as the 7805 and LM317, comparators, phase-locked loops and data converters.

What is the difference between linear and digital ICs?

Linear ICs handle signals that can take any value within a range, such as audio or sensor outputs, and their output is proportional to their input. Digital ICs handle only two levels, representing 0 and 1, and perform logic, counting and storage. Many systems use both together.

What are the pins of IC 741?

Pin 2 is the inverting input, pin 3 the non-inverting input, pin 4 the negative supply, pin 6 the output and pin 7 the positive supply. Pins 1 and 5 are used for offset null adjustment, and pin 8 has no connection in the standard 8-pin package.

What are the typical specifications of the 741 op-amp?

Typical values are an open-loop gain of about 200,000, input resistance of 2 megohms, output resistance of 75 ohms, input offset voltage of 1 millivolt, CMRR of 90 decibels and slew rate of 0.5 volts per microsecond. An ideal op-amp would have infinite or zero values instead.

How do you calculate the frequency of a 555 astable?

Calculate the high time as 0.693 times RA plus RB times C, and the low time as 0.693 times RB times C. Add them for the period and take the reciprocal. With RA of 4.7 kilohms, RB of 10 kilohms and 10 nanofarads, the frequency is about 5,842 hertz.

Why is the 555 astable duty cycle above 50 per cent?

The timing capacitor charges through both RA and RB but discharges through RB alone, so the high time is always longer than the low time. Adding a diode across RB makes the capacitor charge through RA only, which allows a duty cycle of 50 per cent or lower.

What is the pulse width of a 555 monostable?

The output pulse width of a 555 monostable is 1.1 times the timing resistance times the timing capacitance. A 100 kilohm resistor with a 10 microfarad capacitor gives a pulse of 1.1 seconds each time the circuit is triggered. The pulse length does not depend on the supply voltage.

How do you set the output of an LM317?

The output equals 1.25 volts multiplied by one plus R2 divided by R1, ignoring the small adjust-pin current. With R1 of 240 ohms, a 5 volt output needs R2 of 720 ohms; the nearest standard value of 750 ohms gives about 5.16 volts.

What is the dropout voltage of a regulator?

Dropout voltage is the minimum difference between input and output at which a regulator can still hold its output steady. For the 78xx series it is about two volts, so a 7805 needs roughly seven volts or more at its input to deliver a stable five volts.

How much heat does a linear regulator produce?

A linear regulator dissipates the input voltage minus the output voltage, multiplied by the load current. A 7805 running from 12 volts and supplying half an amp dissipates 3.5 watts, which needs a heatsink. Higher input voltages waste more power, which is why switching regulators are often preferred.

What is a Schmitt trigger?

A Schmitt trigger is a comparator with positive feedback that gives two switching thresholds instead of one. The output changes state only when the input rises above the upper threshold or falls below the lower one, so noise smaller than the hysteresis gap cannot cause false switching.

How do you calculate Schmitt trigger thresholds?

Find the feedback fraction, R2 divided by R1 plus R2, and multiply it by the positive and negative saturation voltages. With saturation at 13 volts, R1 of 10 kilohms and R2 of 2.2 kilohms, the thresholds are about plus and minus 2.34 volts, giving 4.69 volts of hysteresis.

What is an instrumentation amplifier used for?

An instrumentation amplifier amplifies the small difference between two signals while rejecting voltages common to both inputs. It has very high input resistance and a high common-mode rejection ratio, making it the standard choice for strain gauges, thermocouples, bridge circuits and medical electrodes such as ECG sensors.

What is the difference between lock range and capture range?

Lock range is the band of input frequencies over which a phase-locked loop stays locked once it has locked. Capture range is the narrower band over which it can acquire lock from an unlocked state. The capture range is always smaller, and it narrows further as the loop filter capacitance increases.

Can a tutor help with linear integrated circuits?

Yes. A one-to-one tutor can work through 555 timer, regulator, Schmitt trigger, instrumentation amplifier, PLL and data converter calculations with you, and check where your working goes wrong. You complete your own assessed work and lab reports in line with your college or university's academic rules.

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